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...Determine the incenter of 3 pionts?
Autor: Arash Partow
Homepage: http://www.partow.net
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Tip Rating (11):  
     


procedure Incenter(const x1, y1, x2, y2, x3, y3: Double; out Px, Py: Double);
var
  
Perim: Double;
  Side12: Double;
  Side23: Double;
  Side31: Double;
begin
  
Side12 := Distance(x1, y1, x2, y2);
  Side23 := Distance(x2, y2, x3, y3);
  Side31 := Distance(x3, y3, x1, y1);

  (* Using Heron's S=UR *)
  
Perim := 1.0 / (Side12 + Side23 + Side31);
  Px    := (Side23 * x1 + Side31 * x2 + Side12 * x3) * Perim;
  Py    := (Side23 * y1 + Side31 * y2 + Side12 * y3) * Perim;
end;
(* End of Incenter *)


function Distance(const x1, y1, x2, y2: Double): Double;
var
  
dx: Double;
  dy: Double;
begin
  
dx     := x2 - x1;
  dy     := y2 - y1;
  Result := Sqrt(dx * dx + dy * dy);
end;
(* End of Distance *)


 

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